Question

A's age is twice of B,B's age is twice that of C and C's age is twice that of D. If the average of the ages of A,B,C and D is 15 years,then what is the present age of B?​

Answer 1

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Answer 2

Answer:

Average = 15⇒ 4Sum=15 ⇒ Sum=60

A+B+C+D = 60

A=2BB=2CC=2D ⇒ 2B=2D ⇒ B=4D

Hence, A+B+C+D=2B+B+2B+4B=415B=60⇒B=16