Question

A's age is twice of his son B's age and C's age is four years less than A's age. If B is 5 years younger than d then what is the average of a,b,c and d together

Answer 1

Let age of B be x then age of is 2x Nd age of C is ( 2x-4) Nd age of d is (x+5) , now average age is given by (x +2x+2x-4+x+5) / 4 = (6x+1)/4