A's income is 60% more than that of B .By what percent is B's income less than A's ?
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Let the salaries of A,B be x,y;
x=y(100160)
(160160−100)100=37.5%
saslray of B is 37.5% less than that of A
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Hey
Let B's income be ₹ 100 .
Then, A's income = ₹ 160 .
If A's income is ₹ 160 , then B's income = ₹ 100
If A's income is ₹ 100 , then B's income = ₹ ( 100 / 160 × 100 ) = ₹ 62.50
So, B's income is less than A's income by ( 100 - 62.50 ) = 37.5 %
Thank You!
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