Math, asked by jaspreet619, 10 months ago

A's present age is double B's present age. 5 years ago the sum of their ages was 35 years. Find their present ages.​

Answers

Answered by karanjotgaidu
1

Answer:

Present age of A is 30 years and B is 15 years

Step-by-step explanation:

Let A's age be x and B's age be y

It is give that x=2y

Five years ago,

A's age = x-5

B's age = y-5

x-5+y-5=35

x+y=45

2y+y=45

3y=45

y=45/3=15

x=2y=2×15=30

PLS MARK AS BRAINLIEST

Answered by Anonymous
1

Let B's present age be x and A's age be 2x

5 years ago

B's age =x-5

A's age =2x-5

Sum of their ages :

(x-5)+(2x-5)=35

3x-10=35

3x=35+10

3x=45

X=45/3

X=15

B's age is x=15

A's age is 2x=2x15=30

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