Question

A salt solution containing 60% salt and another salt solution containing 30% salt are mixed so as to get 20 litres of a 45% salt solution. Find how many litres of each type of solution should be mixed so as to achieve the desired result. ( Best will be marked as brainliest )

Answer 1

Consider 1 litre of the first solution, it contains 600ml salt and 400 ml water.
Consider 1 litre of the second solution, it contains 300 ml salt and 700 ml water.
If we add these two we get
2 Litre solution with 900 ml salt and 1100 ml water
Already we can see that % of the salt in this solution is 45%.
Hence we know that equal volumes of the two solutions must be mixed to get a 45 % salt solution.
Hence the total volume is 20 litres, 10 litres of each solution must be mixed to achieve the desired result.

Answer 2

Answer:

Here percentage of salt in second solution is missing.

So let us take it to be 30%

Let quantity of 60% solution mixed be x l and that of 30% solution be y lNow total quantity of the mixture is given 20 lHence x+y = 20 .........(1)Also concentration of salt in 60% solution+ concentration of salt in 30% solution= concentration of salt in 40% solutionHence 60% of x + 30% of y = 45% of 20⇒60100x+30100y = 45100×20=60x+30y =900⇒2x+y=30...........(2)Now subtracting (1) from (2) we getx =10Putting x=10 in (1) we get,y = 10Hence quantity of 60% solution to be mixed is 10 l and quantity of 30% solution to be mixed is 10 l