A sample CaCO3 contains 20% non volatile impurities. Calculate the mass of the solid residue left after the decomposition of 10g sample.
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Answer:
CaCO
3
(s)
→
CaO(s)
Residue
+
CO
2
(g)
100
grams of calcium carbonate liberates approximately
22.4
x
L
carbon dioxide at
STP
,
0
∘
C
and
1 atm
pressure because it's about
1 mol
of
CaCO
3
.
Because volume is extensive,
⇒
10
grams of calcium carbonate liberates
22.4
×
10
100
x
L
carbon dioxide
=
2.24
L
carbon dioxide.
Explanation:
hope this is help u
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