Question

A sample of 5.04g of oxide for phosphorus contains 2.48g of phosphorus. [relative atomic mass: O=16, F=31]

a) if the relative molecular mass of the oxide is 126, determine its empirical formula and molecular formula.

b) name the oxide of the phosphorus.

Answer 1

Answer:a) empirical formula:PO2

Molecular formula:P2O4

Explanation:

Element: P | O

Mass(g) 5.04-2.48.| 2.48

=2.56

Mole(mol) 2.56 divide 31 | 2.48 divide 16

(molar mass of P) (molar mass of O)

=0.08. =0.16

Ratioofmoles: 0.08divide0.08| 0.16 divide 0.08

=1. =2

simplest ratio: 1 | 2

Empirical formula : PO2

Molecular formula :(PO2)n = 126

31+2(16)n=126

63n=126

n=2

(PO2)2=P2O4