Prove that, sin28° + √2 sin 17° = cos28°
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12√12 sin 28° cos 17° + cos 28° sin 17° = sin(28° + 17°) This is of the form sin(A + B), A = 28°, B = 17° = sin 45° = 12√Read more on Sarthaks.com - https://www.sarthaks.com/981143/the-value-of-sin-28-cos-17-cos-28-sin-17-a-1-2-b-1-c-1-2-d-0
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