A sample of a compound contains 9.75 g zn, 1.8 × 1023 atoms of cr and 0.6 gram-atoms of o. What is empirical formula of compound ? (atomic mass zn = 65)
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Answer:
ZnCr2O4
Explanation:
(1st 2 steps are in the attachment)
3) Form the empirical formula:-
Zn - 1
Cr - 2
O - 4
Therefore, the empirical formula = ZnCr2O4
I think this is the answer!
Hope this helps!
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