Question

A sample of a monatomic ideal gas is originally at 20 °C. What is the final temperature of the gas if the pressure is doubled and volume is reduced to one-fourth its initial value?

Answer 1

Explanation:

$\frac{p}{4p} \times \frac{4v}{v} = \frac{20}{t} \\ t = 20 \: degrees$

hence temperature remains same