Question

a sample of air has a volume of 500dm³ and pressure of 1 bar. what additional pressure is required the volume to 200dm³ to 30 c​

Answer 1

Explanation:

According to ideal gas equation, P

1

V

1

=P

2

V

2

Here P

1

=1bar,V

1

=500dm

3

,V

2

=200dm=

200

1×500

=2.5bar

Answer 2

Answer:

Volume of gas(V1) = 500dm3 (given)

Pressure of gas (p1) = 1 bar (given)

Volume of compressed gas (V2) = 200dm3 (given)

Now ,let P2 be the pressure required to compress the gas.

Therefore at constant temperature P1 V1 = P2 V2 (Boyle’s Law)

As a result P2 = P1 V1 / V2 = 1 X 500/200 = 2.5 bar

Therefore, the minimum pressure required is 2.5 bar.

hope it will help u..