Question

a sample of ammonia weighs 2.00g.what mass of sulphur dioxide contains the same number of molecules as are in 2.00g ammonia

Answer 1

moles of ammonia = 2/17 17 is mass of ammonia.

moles of ammonia = moles of Sulpher dioxide

2/17 = X/64
x = 2×64/17
= 128/17
7.529 g

hope this helps.

Answer 2

Answer: 7.52 g of sulfur dioxide contains the same number of molecules as are in 2.00 g ammonia

Explanation:

Mass of the ammonia = 2.00 g

Moles of ammonia=$\frac{\text{Given mass}}{\text{molar mass}=\frac{2.00 g}{17 g/mol}=0.1176 moles</p><p>Number ammonia molecules = [tex]\text{Number of moles}\times N_A=0.1176\times 6.022\times 10^{23}=7.08\times 10^{22} molecules$

For same number molecule for $SO_2$

Number $SO_2$ molecules = $\text{Number of moles of }SO_2\times N_A=0.117\times 6.022\times 10^{23}$

$\text{Number of moles of }SO_2=\frac{7.08\times 10^{22} molecules}{6.022\times 10^{23}}=0.1175 moles$

Mass of $SO_2=0.1175 moles\times 64g/mol=7.52 g$

7.52 g of sulfur dioxide contains the same number of molecules as are in 2.00 g ammonia