Chemistry, asked by anjalisharmaorchid9, 3 months ago

A sample of ammonia weighs 4 g. What mass of sulphur dioxide contains the same number of molecules as are in 4 g of ammonia? full explanation pls!!!!! Fast!!!!​

Answers

Answered by LionKingKsd
8

Answer:

15.058g

Explanation:

The no. of moles of ammonia in 4g of ammonia = 4/17

If no. of atoms are equal , no. of moles will also be equal.

Hence no. of moles of sulphur dioxide = 4/17

Therefore the weight of 4/17 moles of sulphur dioxide = 64×4/17 = 256/17 = 15.058g

Answered by nishthak9785
2

Answer:

mass of ammonia=4g

molar mass of ammonia=17g/mole

that's why no.of moles of ammonia=4/17 mole

let mass of sulphur dioxide is x.

amt. of sulphur dioxide=mass of SO2/molar mass of SO2

=x\64mol

=4/17

x=4*16/17

=15.05g

=approximately 15g

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