Question

A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answer 1

Answer:

0.193J$g^{-1} K^{-1}$

Explanation:

Q= mcΔT

rearrange to c= Q/(mΔT)

ΔT= (305-285)= 20

So,,

c=345.2/ (89.5 x 20)

c=0.193J$g^{-1} K^{-1}$

Hope this helps you,,,

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Answer 2

Answer:

part one: 0.193

part two: 37.9

Explanation: