A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?
Answers
Answered by
3
Answer:
0.193J
Explanation:
Q= mcΔT
rearrange to c= Q/(mΔT)
ΔT= (305-285)= 20
So,,
c=345.2/ (89.5 x 20)
c=0.193J
Hope this helps you,,,
¶ THANK YOU ¶ ,
Answered by
0
Answer:
part one: 0.193
part two: 37.9
Explanation:
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