Chemistry, asked by yashula, 1 year ago

A sample of clay is found to have formula Al2O3.K2O.6SiO2.
Calculate the percentage of Alumina, Potassium oxide and Silica in the sample.​

Answers

Answered by kobenhavn
32

Answer: The percentage of Alumina, Potassium oxide and Silica in the sample is 18.3 , 16.9 and 64.6 respectively.

Explanation:

In Al_2O_3.K_2O.6SiO_2, alumina Al_2O_3 has 2 aluminium atoms and 3 oxygen atoms, silica 6SiO_2 has 6 silicon atoms and 12 oxygen atoms and potassium oxide K_2O has 2 potassium atoms and 1 oxygen atom.

To calculate the mass percent of compounds, we use the formula:

\text{Mass percent of alumina}=\frac{\text{Mass of alumina}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100

Putting values in above equation, we get:

\text{Mass percent of alumina}=\frac{102}{557}\times 100=18.3\%  

2. \text{Mass percent of potassium oxide}=\frac{\text{Mass of potassium oxide}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100

Putting values in above equation, we get:

\text{Mass percent of potassium oxide}=\frac{94}{557}\times 100=16.9\%

3. \text{Mass percent of silica}=\frac{\text{Mass of silica}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100

Putting values in above equation, we get:

\text{Mass percent of silica}=\frac{360}{557}\times 100=64.6\%

Answered by rsultana331
3

Answer:

Answer: The percentage of Alumina, Potassium oxide and Silica in the sample is 18.3 , 16.9 and 64.6 respectively.

Explanation:

In Al_2O_3.K_2O.6SiO_2Al

2

O

3

.K

2

O.6SiO

2

, alumina Al_2O_3Al

2

O

3

has 2 aluminium atoms and 3 oxygen atoms, silica 6SiO_26SiO

2

has 6 silicon atoms and 12 oxygen atoms and potassium oxide K_2OK

2

O has 2 potassium atoms and 1 oxygen atom.

To calculate the mass percent of compounds, we use the formula:

\text{Mass percent of alumina}=\frac{\text{Mass of alumina}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100Mass percent of alumina=

Molar mass ofAl

2

O

3

.K

2

O.6SiO

2

Mass of alumina

×100

Putting values in above equation, we get:

\text{Mass percent of alumina}=\frac{102}{557}\times 100=18.3\%Mass percent of alumina=

557

102

×100=18.3%

2. \text{Mass percent of potassium oxide}=\frac{\text{Mass of potassium oxide}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100Mass percent of potassium oxide=

Molar mass ofAl

2

O

3

.K

2

O.6SiO

2

Mass of potassium oxide

×100

Putting values in above equation, we get:

\text{Mass percent of potassium oxide}=\frac{94}{557}\times 100=16.9\%Mass percent of potassium oxide=

557

94

×100=16.9%

3. \text{Mass percent of silica}=\frac{\text{Mass of silica}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100Mass percent of silica=

Molar mass ofAl

2

O

3

.K

2

O.6SiO

2

Mass of silica

×100

Putting values in above equation, we get:

\text{Mass percent of silica}=\frac{360}{557}\times 100=64.6\%Mass percent of silica=

557

360

×100=64.6%

Explanation:

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