A sample of clay is found to have formula Al2O3.K2O.6SiO2.
Calculate the percentage of Alumina, Potassium oxide and Silica in the sample.
Answers
Answer: The percentage of Alumina, Potassium oxide and Silica in the sample is 18.3 , 16.9 and 64.6 respectively.
Explanation:
In , alumina has 2 aluminium atoms and 3 oxygen atoms, silica has 6 silicon atoms and 12 oxygen atoms and potassium oxide has 2 potassium atoms and 1 oxygen atom.
To calculate the mass percent of compounds, we use the formula:
Putting values in above equation, we get:
2.
Putting values in above equation, we get:
3.
Putting values in above equation, we get:
Answer:
Answer: The percentage of Alumina, Potassium oxide and Silica in the sample is 18.3 , 16.9 and 64.6 respectively.
Explanation:
In Al_2O_3.K_2O.6SiO_2Al
2
O
3
.K
2
O.6SiO
2
, alumina Al_2O_3Al
2
O
3
has 2 aluminium atoms and 3 oxygen atoms, silica 6SiO_26SiO
2
has 6 silicon atoms and 12 oxygen atoms and potassium oxide K_2OK
2
O has 2 potassium atoms and 1 oxygen atom.
To calculate the mass percent of compounds, we use the formula:
\text{Mass percent of alumina}=\frac{\text{Mass of alumina}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100Mass percent of alumina=
Molar mass ofAl
2
O
3
.K
2
O.6SiO
2
Mass of alumina
×100
Putting values in above equation, we get:
\text{Mass percent of alumina}=\frac{102}{557}\times 100=18.3\%Mass percent of alumina=
557
102
×100=18.3%
2. \text{Mass percent of potassium oxide}=\frac{\text{Mass of potassium oxide}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100Mass percent of potassium oxide=
Molar mass ofAl
2
O
3
.K
2
O.6SiO
2
Mass of potassium oxide
×100
Putting values in above equation, we get:
\text{Mass percent of potassium oxide}=\frac{94}{557}\times 100=16.9\%Mass percent of potassium oxide=
557
94
×100=16.9%
3. \text{Mass percent of silica}=\frac{\text{Mass of silica}}{\text{Molar mass of} Al_2O_3.K_2O.6SiO_2}\times 100Mass percent of silica=
Molar mass ofAl
2
O
3
.K
2
O.6SiO
2
Mass of silica
×100
Putting values in above equation, we get:
\text{Mass percent of silica}=\frac{360}{557}\times 100=64.6\%Mass percent of silica=
557
360
×100=64.6%
Explanation: