Chemistry, asked by Mantu208, 11 months ago

A sample of (d)lactic acid was found to have an optical purity of . How much isomer is present in the sample?

Answers

Answered by Anonymous
1

Answer:

Here we will have to find out how much R-isomer is present in the sample. Let the total % of the enantiomeric mixture is 100%. The optical activity is 72% means, the enantiomer has 72% of excess S-isomer and 28% racemic mixture

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