A sample of drinking water contains 11.95 ppm of chloroform. The molality of sample is
0 10 m
0 10 7 m
0 10² m
0 10 m
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Correct Question:
A sample of drinking water contains 11.95 ppm of chloroform. The molality of the sample is :
(a) 10 m
(b) 10 7 m
(c) 10² m
(d) 10⁻⁴ m
Correct Answer:
Given:
The concentration of chloroform = 11.95 ppm
To Find:
The molality of the given chloroform sample.
Calculation:
- The molar mass of chloroform = 119.5 gm/mol
- ppm concentration = (w / W) × 10⁶
⇒ 11.95 = (w / W) × 10⁶
⇒ w = 11.95 × 10⁻⁶ × W
- Molality = (w × 1000) / (M.wt × W)
⇒ m = (11.95 × 10⁻⁶ × W × 1000) / (119.5 × W)
⇒ m = 0.1 × 10⁻³
⇒ m = 10⁻⁴ m
- So, the correct answer is (d) 10⁻⁴ m.
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