A sample of fe2+ contains 8 x 10^5 coulomb charge.Find out weight of sample.
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Explanation:
1 e =1.6×10^-19c
2e=2×1.6×10^-19=3.2×10^-19c
charge of 1 ion of fe2+ is 3.2×10^19c
total charge =8×10^5c
now we will find no of moles o fe2+ ion
n×3.2×10^-19=8×10^5
n=8×10^5/3.2×10^-19=2.5×10^24moles of fe 2+ions
moles=mass/molar mass
2.5×10^24=mass/55. 845
mass=139.6125×10^24g
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