Question

A sample of gas absorbs 4000 kJ of heat, if volume remain constant , what is ΔU?
(4000kJ)

Answer 1

$\huge{\texbf\red{ANSWER }}}$

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$\huge{\texbf\red{GIVEN }}}$

Q= 4000kJ heat

Volume =V= constant

$\huge{\texbf\red{REQUIRED }}}$

delta U = ?

$\huge{\texbf\red{SOLUTION }}}$

First of all I shoukd make it clear that If Volume is constant Work done is Zero

$\huge{\texbf\red{REASON }}}$

If volume is constant there is no change in the volume So no work is done on the system therefore work done is equal to zero

USING FIRST LAW OF THERMODYNAMICS

delta Q=delta U + delta W

Work done is zero ,So

delta Q = delta U + 0

delta Q = delta U ---------1

As it is given that heat absorbed is 4000kJ , So

delta Q = 4000kJ

Therefore from relation 1 it is clear that internal energy is equal to heat absorbed If Work done is zero .

delta Q = delta U

SO delta U = 4000kJ


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