Question

The oxidation of one mole of SO at 50°C.
2SO₂ (g) + O₂ (g) → 2SO₃ (g)

Calculate the work done in above reaction . State whether work is done on or by the system.

Answer 1

Answer:

W.d = -2685.422 j(Work is done on the system).

Explanation:

Since we know that the work done for the reaction is given by = $\int{-pdv}$.....................(1)

we know the ideal gas equation $PV = nRT$.................(2)

differentiating both sides we get

$PdV = nRdT$............................(3)

From (1) and (3)

So, work done = $\int {-nRdT}$ = -nRT

We have n=1 R = 8.314 J/kg K ,T=273+50=323 K

So,work done = $-1\times 8.314 \times 323$ = -2685.422 joules.

Since work done is negative so,work is done on the system.

Answer 2

Answer:

4.955J

Work is done on the system (W >0) hence it is positive