Question

A sample of gas occupies 10 L . under a pressure of 1 atm. what will be its volume if the pressure is increased to 2 atm ? Assuming that temperature of the gas sample does not change .​

Answer 1

Answer: 5 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$     (At constant temperature and number of moles)

$P_1V_1=P_2V_2$  

where,

$P_1$ = initial pressure of gas  = 1 atm

$P_2$ = final pressure of gas  = 2 atm

$V_1$ = initial volume of gas  = 10 L

$V_2$ = final volume of gas  = ?

$1\times 10=2\times V_2$  

$V_2=5L$

Therefore, the volume of the gas will be 5 L when  pressure is increased to 2 atm .

Answer 2

Answer:

5L

Explanation:

Here we have to use the formula P1V1=P2V2.

P1=1 V1=10 P2=2 we have to find V2

So V2 will be equal to

V2=P1*V1/P2

1*10/2

=5 L

Hence 5L is the answer