Question

A sample of gulcose is labelled 10 percent weight by weight calculate molality

Answer 1

Hi it's your answer....
Molality = number of moles of solute/mass of solvent in Kg ……(1)
Now we have to find number of moles and mass of solvent in Kg both
mass of solute = mass of glucose /molar mass of glucose …..(2)

Molar mass of glucose (C6H12O6) = 6*C + 12*H + 6*O
= 6*12 + 12*1 + 6*16
=180 g /mol
Putting the value back in equation (2) we get
Number of moles = 10/180 = 0.0556 moles
We have mass of solvent (H2O) = Mass of solution – Mass of solute
= 100g- 10g
= 90 g
Mass in Kg = 90 g* 1 Kg / 1000 g = 0.09 Kg
Putting the value in equation (1) we get
Molality = 0.0556/0.09 = 16.7M

Answer 2

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