Question

A sample of HCI gas is placed in an electric field of 2.5 × 104 NC−1. The dipole moment of each HCI molecule is 3.4 × 10−30 Cm. Find the maximum torque that can act on a molecule.

Answer 1

8.5 × $10^{-26}$ Nm maximum torque capable of acting on a molecule.

Explanation:

Step 1:

Given values  

intensity of electric field , E = 2.5 × 104 NC−1

Dipole moment of a molecule of HCl, P = 3.4 × 10−30 Cm

Torque on the molecule,

Step 2:

Formula used: It gives the torque acting on a dipole

Γ=P×E  

Where

The torque operates on the dipole, the dipole moment of the HCl molecules is P, and the electrical field is E.

Step 3:

Γ = PE sinθ

For                                                            

Γmax putting sinθ = 1

we get

Γmax = PE  = 3.4 × $10^{-30}$ × 2.5 × 104  

 = 8.5 × $10^{-26}$ Nm

8.5 × $10^{-26}$ Nm maximum torque capable of acting on a molecule.