Question

The compressibility factor Z = PV/RT for 1 mol of a real gas is
greater than unity at a pressure of 1 atm and 273 .15 K. The
molar volume of the gas at STP will be
(a) less than 22.4 L (b) greater than 22.4 L
(c) equal to 22.4 L (d) none of these

Answer 1

answer : option (b) greater than 22.4 L

The compressibility factor, Z = PV/RT for one mole of real gas is greater than unity at a pressure of 1atm and 273.15 K.

actually, compressibility factor , Z = PV_m/RT > 1

⇒1atm × V_m/1mol × 0.0821 atm.Litre/mol.K × 273.15 K > 1

⇒V_m/0.0821 × 273.15 L > 1

⇒V_m/22.4 > 1

⇒V_m > 22.4 L

hence molar volume of gas is greater than 22.4 L

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