Question

a sample of helium has volume of 520mL at 100°C. calculate the temperature at which the volume becomes 260mL assume that the pressure is constant​

Answer 1

Answer: V1/T1=V2/T2

500/373=260/T2

T2=(260x373)/500

=193.96 k

Explanation:

Answer 2

The temperature at which the volume becomes 260mL assume that the pressure is constant​ is 186.5 K

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=520ml\\T_1=100^oC=(100+273)K=373K\\V_2=260ml\\T_2=?$

Putting values in above equation, we get:

$\frac{520}{373}=\frac{260}{T_2}\\\\T_2=186.5K$

Thus the temperature at which the volume becomes 260mL assume that the pressure is constant​ is 186.5 K

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