A sample of helium measuring 6L was kept at a pressure of 1.5atm. If the pressure is doubled what would be its new volume
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Answer:
3L
Explanation:
The following data were obtained from the question:
V1 (original volume) = 6L
P1 (original pressure) = 1.5 atm
P2 (new pressure) = 2 x P1 ( since the new pressure is doubled)
P2 = 2 x 1.5
P2 = 3 atm
V2 (new volume) =?
Using the Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:
P1V1 = P2V2
1.5 x 6 = 3 x V2
Divide both side by 3
V2 = (1.5 x 6)/3
V2 = 3L
From our calculations, the new volume will be half the original volume and this will be 3L
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Answer:
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