Question

A sample of HNO3 has a density of 1.41gmL−1 find the concentration of HNO3 in moles per litre and the mass percent of HNO3 in it is 69%.

Answer 1

Ans-15.4mole/Litre............

Answer 2

Answer:

Molarity = 15.439 M

Explanation:

Moles per liter means Molarity.

Molarity is define as numbers of moles of solute present in unit volume of solution in litre.

We have formula for Molarity.

$\displaystyle Molarity=\frac{numbers \ of \ moles \ of \ solute}{volume \ of \ solution \ in(L)}$

We have other Molarity formula in terms of density.

Molarity = n × d × 10

where n = numbers of moles of solute

d = density of solution.

Given d = 1.41 g / m L

Molar mass = 63 g.

Given mass = 69 % = 69 g

First let us find n.

n = given mass / molar mass

n = 69 / 63 = 1.095

Now put the value of d and n in formula we get

Molarity = 1.41 × 1.095 × 10 M

Molarity = 15.439 M

Molarity = 15.44 M

Thus we get answer.