Question

a sample of iron containing 60% of iron 56 and 10% of fe57 and 30% of iron 58. in this sample iron 57 is added from outside so that its percent become 28 what is the mass number of the sample ​

Answer 1

Answer:

56.76

Explanation:

let x fe 57 be added then

10+x/100+x =28/100

x=25

new percentage

fe56 = 60/125 ×100=48

fe 57= 28

fe58=30/125 ×100=24

now mass number =(56*48+57*28+58*24)/100

=56.76