Chemistry, asked by Tracey98, 9 months ago

A sample of lithium has a mass of 0.0624 grams. How many atoms are present in this sample?

Answers

Answered by dipamcool2016
0

Answer:

One mole of Li is of:

7 g

So, in 0.0624 g of Li, moles present is:

= 0.0624/7

= 0.0089

In 0.0089 moles, the no. of atoms are:

= 0.0089*6.022*10^24

= 0.0536*10^24

or,

= 5.36*10^22

Hope this helps.

Answered by jesusbolanos2168
0

Answer:

Correct answer:

5.41×1021 atoms

Explanation:

To determine the number of atoms present in a 0.0624 grams sample of lithium, we need to divide by the molar mass and multiply by Avogadro's number.

0.0624 g×1 mol Li6.94 g×6.022×1023 atoms1 mole=5.41×1021 atoms

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