A sample of lithium has a mass of 0.0624 grams. How many atoms are present in this sample?
Answers
Answered by
0
Answer:
One mole of Li is of:
7 g
So, in 0.0624 g of Li, moles present is:
= 0.0624/7
= 0.0089
In 0.0089 moles, the no. of atoms are:
= 0.0089*6.022*10^24
= 0.0536*10^24
or,
= 5.36*10^22
Hope this helps.
Answered by
0
Answer:
Correct answer:
5.41×1021 atoms
Explanation:
To determine the number of atoms present in a 0.0624 grams sample of lithium, we need to divide by the molar mass and multiply by Avogadro's number.
0.0624 g×1 mol Li6.94 g×6.022×1023 atoms1 mole=5.41×1021 atoms
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