A sample of municipal water contains one part of urea (m.wt=60) per million parts of water by weight. The number of urea molecules in a drop of water of volume 0.05ml is?
Answers
Given:
- Municipal water contains one part of urea per million parts of water by weight.
To Find:
- The number of urea molecules in a drop of water of volume
Solution:
Taking into account that means urea is in of water
The mass of urea in 0.05 g
Then the number of moles for urea is defined by
Here,
– mass of urea
– molecular weight of urea being of 60 g/mol.
Thus,
The number of urea molecules
Where
– the Avogadro constant
Thus,
The number of urea molecules in a drop of water of volume is
Answer:
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Explanation:
Taking into account that 1 ppm1ppm means 1 mg1mg urea is in 1000 g1000g of water
The mass of urea in 0.05 g
m = \frac{1 mg \times 0.05 g }{1000g} = 5 \times 10^{-8}g.m=
1000g
1mg×0.05g
=5×10
−8
g.
Then the number of moles for urea is defined by
\nu = \frac{m}{M_w}ν=
M
w
m
Here,
mm – mass of urea
M_wM
w
– molecular weight of urea being of 60 g/mol.
Thus,
\nu = 5 \times 10^{-8} g /60 g mol^{-1} = 0.08333 \times 10^{-8} moleν=5×10
−8
g/60gmol
−1
=0.08333×10
−8
mole
The number of urea molecules
N = \nu \times N_aN=ν×N
a
Where
N_aN
a
– the Avogadro constant (6.02 \times 10^{23} mole^{-1})(6.02×10
23
mole
−1
)
N = 0.08333 \times 10^{-8} \ mole \times 6.02 \times 10^{23} \ mole^{-1}N=0.08333×10
−8
mole×6.02×10
23
mole
−1
= 0.502 \times 10^{15} \ molecules=0.502×10
15
molecules
Thus,
The number of urea molecules in a drop of water of volume 0.05ml0.05ml is 0.502 \times 10^{15} \ molecules0.502×10
15
molecules