Science, asked by priyusha, 1 year ago

A sample of municipal water contains one part of urea (m.wt=60) per million parts of water by weight. The number of urea molecules in a drop of water of volume 0.05ml is?​

Answers

Answered by roshinik1219
4

Given:

  • Municipal water contains one part of urea (m.wt=60) per million parts of water by weight.

To Find:

  • The number of urea molecules in a drop of water of volume 0.05ml

Solution:

Taking into account that 1 ppm means 1 mg urea is in 1000 g of water

The mass of urea in 0.05 g

                  m = \frac{1 mg \times 0.05 g }{1000g}  = 5 \times  10^{-8}g.

Then the number of moles for urea is defined by

             \nu =  \frac{m}{M_w}

Here,

m – mass of urea

M_w – molecular weight of urea being of 60 g/mol.

Thus,

           \nu = 5 \times 10^{-8} g /60 g mol^{-1} = 0.08333 \times 10^{-8} mole

The number of urea molecules  

N = \nu \times N_a

Where

N_a – the Avogadro constant (6.02 \times  10^{23} mole^{-1})

N = 0.08333 \times 10^{-8} \ mole \times 6.02 \times 10^{23} \ mole^{-1}

    = 0.502 \times  10^{15} \ molecules

Thus,

The number of urea molecules in a drop of water of volume 0.05ml is 0.502 \times  10^{15} \ molecules

Answered by arunkumaramireddy22
0

Answer:

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Explanation:

Taking into account that 1 ppm1ppm means 1 mg1mg urea is in 1000 g1000g of water

The mass of urea in 0.05 g

m = \frac{1 mg \times 0.05 g }{1000g} = 5 \times 10^{-8}g.m=

1000g

1mg×0.05g

=5×10

−8

g.

Then the number of moles for urea is defined by

\nu = \frac{m}{M_w}ν=

M

w

m

Here,

mm – mass of urea

M_wM

w

– molecular weight of urea being of 60 g/mol.

Thus,

\nu = 5 \times 10^{-8} g /60 g mol^{-1} = 0.08333 \times 10^{-8} moleν=5×10

−8

g/60gmol

−1

=0.08333×10

−8

mole

The number of urea molecules

N = \nu \times N_aN=ν×N

a

Where

N_aN

a

– the Avogadro constant (6.02 \times 10^{23} mole^{-1})(6.02×10

23

mole

−1

)

N = 0.08333 \times 10^{-8} \ mole \times 6.02 \times 10^{23} \ mole^{-1}N=0.08333×10

−8

mole×6.02×10

23

mole

−1

= 0.502 \times 10^{15} \ molecules=0.502×10

15

molecules

Thus,

The number of urea molecules in a drop of water of volume 0.05ml0.05ml is 0.502 \times 10^{15} \ molecules0.502×10

15

molecules

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