Question

A sample of NaNO3 weighing 0.38 g is placed in a 50.0 mL volumetric flask. The flask is then
filled with water to the mark on the neck. What is the molarity of the solution?
A
8.94 x 10-6M
G
B
8.94 x 10-2M
с
1.94 x 10-2M
D
8.94 x 10-4M​

Answer 1

Answer:

Answer=>(B)8.94 x 10-2M

Molarity×VolumeinmL=Milli−mole=W/M×1000

∴Molarity×50=0.38/85×1000

[Mol. wt. of NaNO3=85]

∴Molarity=8.94×10^−2

Explanation:

Hope this helps you.

Answer 2

Answer:

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