Question

:A sample of Ne gas occupies 0.220L at 0.86 atm. What will be its volume at
29.4kPa​

Answer 1

Answer:

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Explanation:

Initial volume=0.220 L

initial pressure =0.860 atm

final volume = ?

final pressure = 29.2 kpa(0.288 atm)

v2=P1v1/P2

=0.860 atm (0.220 L) / 0.288 atm

=0.657 L

P=⬇

V=⬆

P inversly proportional 1/v

Answer 2

Answer:

The volume of Neon gas is 0.657 L.

Explanation:

• A neon gas is termed as Ne a chemical element.
• The gas of the inert is of group number 18 which is noble gas of any periodic table.
• They are colorless, odorless, tasteless and very light compared to the air.
• It occurs in the presence of Earth’s atmosphere.
• The gas can be found in parts of the atmosphere of the earth and crust of the Earth.

Given that:

Ne gas = 0.220 L

Atmosphere = 0.86

Kpa = 19.4

To find:

The volume of neon gas =?

Solution:

By applying the formula for volume, we get,

$V_{2} =p_{1} * v_{1} / p_{2}$

$V_{2}$  = 0.860*(0.220) / 0.288

$V_{2}$  = 0.657 L

Therefore, the volume of the Neon gas is 0.657 L.

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