Question

A sample of neon gas at 50°C and a volume of 2.5 litres is cooled to 25°C. What is the new volume?

Answer 1

Answer:

So, there will be 0.122 moles of oxygen gas.

Answer 2

Answer:

The new volume of the neon gas is 2.30L.

Explanation:

From the Charles law we know that the volume of a gas is directly proportional to its absolute temperature. Which is given as,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$       (1)

Where,

V₁=initial volume of the gas

T₁=final volume of the gas

V₂=final volume of the gas

T₂=final temperature of the gas

From the question we have,

V₁=2.5L

T₁=50°C+273=323K

T₂=25°C+273=298K

By substituting the values in equation (1) we get;

$\frac{2.5}{323}=\frac{V_2}{298}$

$V_2=\frac{2.5\times 298}{323}=2.30L$

Hence, the new volume of the neon gas is 2.30L.