A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. What pressure will the sample have at 0.0˚C ?
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Answered by
1
In this question we will use the ideal gas equation.
P
1
x
V
1
/
T
1
=
P
2
x
V
2
/
T
2
P
1
= 2 atm
V
1
= 500 mL
T
1
= 25 + 273 = 298 K
P
2
= ?
V
2
= 500 mL
T
2
= 0 + 273 = 273 K
substituting values;
2 atm x 500 mL / 298 K =
P
2
x 500 mL / 273
rearranging we get,
1000 atm mL x 273 K / 500 mL x 298 K =
P
2
P
2
= 1.83 atm.
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