Question

calculate mass and volume of oxygen required at S.T.Pto convert 3.2 kgs sulphur into SO2

Answer 1

Mass of oxygen in same as sulphur because the contain same no of mole as reaction tells that
S + O2 = SO2
Mole of oxygen required is same as sulphur thus moles of S is 3.2/32= 0.1 moles is same for oxygen and at STP
1 mole = 22.4 litre
0.1 mole = ?
Its 22.4 * 0.1 = 2.24