Question

a sample of oleum is labeled as 118 .moles of naoh needed for complete neutralization of 100 gm oleum is (a) 2 (b) 20/49 (c)118/49 (d) 59/49

Answer 1

118% oleum means...100gm sample and 18gm is the water requried to combine so3 in the sample....1mole of so3 =80 gms..1mol of H20=18gm...1mol of H20 combines 1mol of so3...then 18gm of water combines 80gm of oleum..this is called free oleum..remaining 20%H2so4