A sample of pure water whatever the source always contains by mass of oxygen and 11.1% by mass of hydrogen
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Mass % of oxygen in H2O = Mass of oxygen in H2OMolar mass of H2O×100⇒1618×100=88.8%. Therefore, a sample of pure water, whatever the source, always contains 88.8% by mass of oxygen and 11.1 % by mass of hydrogen. thus the answer is 88.8
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