Question

a sample of sulphuric acid is 98% by mass and has a density of 2g/cc. Calculate the volume of 8N NaOH required to neutralize 50 ml of this acid​

Answer 1

Answer:

ANSWER

98% by weight of solution means 98g of H2SO4 is present in 100g of solution.

Volume of solution =density of solutionmass of solution=(1.8×1000)g/L100g

Volume of solution =181L

Per cent  H2SO4 w/v of solution = molarity =volume of solution (in L)number of moles of H2SO4

Molarity =volume of solutiongiven mass of H2SO4/ molar mass of H2SO4

Molarity =1/1898/98=18M

Answer 2

Answer:

98% by weight of solution means 98g of H

2

SO

4

is present in 100g of solution.

Volume of solution =

density of solution

mass of solution

=

(1.8×1000)g/L

100g

Volume of solution =

18

1

L

Per cent H

2

SO

4

w/v of solution = molarity =

volume of solution (in L)

number of moles of H

2

SO

4

Molarity =

volume of solution

given mass of H

2

SO

4

/ molar mass of H

2

SO

4

Molarity =

1/18

98/98

=18M