Question

A sample of water has 20 ppm degree of hardness. What is the amount of mgso4 present in per kg of water

Answer 1

Given:

The hardness of water = 20 ppm

To Find:

The amount of MgSO4 present in per kg of water.

Calculation:

- 20 ppm hardness = 20 mg CaCO3 in 10⁶ mg water

⇒ 20 ppm hardness = 0.02 gm CaCO3 in 1 kg of water.

- We know that 100 gm CaCO3 ≡ 120 gm MgSO4

⇒ 0.02 gm CaCO3 ≡ (120/100) × 0.02 gm MgSO4

⇒ 0.02 gm CaCO3 ≡ 0.024 gm MgSO4

- Hence, the amount of MgSO4 present is 0.024 gm/kg of water.