A sample of water has 20 ppm degree of hardness. What is the amount of mgso4 present in per kg of water
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Given:
The hardness of water = 20 ppm
To Find:
The amount of MgSO4 present in per kg of water.
Calculation:
- 20 ppm hardness = 20 mg CaCO3 in 10⁶ mg water
⇒ 20 ppm hardness = 0.02 gm CaCO3 in 1 kg of water.
- We know that 100 gm CaCO3 ≡ 120 gm MgSO4
⇒ 0.02 gm CaCO3 ≡ (120/100) × 0.02 gm MgSO4
⇒ 0.02 gm CaCO3 ≡ 0.024 gm MgSO4
- Hence, the amount of MgSO4 present is 0.024 gm/kg of water.
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