(sin A+tan A-1) (sec A-tan A+1)=2 tan A
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Answer:
(secA+tanA-1)(secA-tanA+1)
=(secA+tanA-1){secA-(tanA-1)}
=sec²A-(tanA-1)²
=sec²A-tan²A+2tanA-1
=1+2tanA-1
=2tanA
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