Question

A sampling tube has an inner diameter of 80mm and outer diameter 88mm. The area of ratio is

Answer 1

Answer:

1.1

Step-by-step explanation:

A sampling tube has an inner diameter of 80mm and outer diameter 88mm. The area of ratio of outer & inner surface is ?

Let Say tube has height = h mm

Inner diameter = 80 mm

Inner Radius = Diameter/2 = 80/2 = 40 mm

Surface Area = 2 Pie R h

Inner Surface Area = 2 Pie 40 h

Outer diameter = 88 mm

Outer Radius = 88/2 = 44 mm

Outer Surface Area = 2 Pie 44 h

Outer Surface Area / inner Surface Area =  (2 Pie 44 h)/(2 Pie 40 h)

=> Outer Surface Area / inner Surface Area =  $\frac{44}{40}$

=> Outer Surface Area / inner Surface Area =  $\frac{11}{10}$

=> Outer Surface Area / inner Surface Area =  1.1

1.1 is the ratio of outer Surface area to Inner Surface Area