Question

A saree is 5 m long and 1.3 m wide. A border of width 25 cm is printed along its sides. Fin
the cost of printing the border at 1 per 10 cm".​

Answer 1

Answer:

Given that :

• A saree is 5 m long and 1.3 m wide.

• A border of width 25 cm is printed along its sides.

To find :

• The cost of printing the border at 1 per 10 cm^2.

Solution

Let ABCD be the saree along with the border.

⇒ AB = 1.3 m and BC = 5 m

$\underline{We \:have\: 1 \:m = 100\: cm}$

⇒ AB = 130 cm

⇒ BC = 500 cm

So, side EF of EFGH(saree without the border) as shown in the figure is given by :-

EF = (AB – 25 – 25) cm

⇒ EF = (130 – 50) cm

∴ EF = 80 cm

Now, we have FG = (BC – 25 – 25) cm.

⇒ FG = (500 – 50) cm

∴ FG = 450 cm

⇒ Area of border = Area of ABCD – Area of EFGH

We know, area of a rectangle =

$\boxed{length × breadth}$

So, we have Area of rectangle ABCD = AB × BC

⇒ Area of ABCD = 130 × 500

∴ Area of ABCD = 65000 cm2

Similarly, we have Area of rectangle EFGH = EF × FG

⇒ Area of EFGH = 80 × 450

∴ Area of EFGH = 36000 cm2

So, Area of border = (65000 – 36000) cm2

∴ Area of border = 29000 cm2

It is given that the cost for printing 10 cm^2 border is Rs. 1.

⇒ Cost of printing 29000 cm2 border 

$= rs.1 \times \frac{29000}{10}$

$\therefore$Rs 2900

Answer 2

$\huge \purple {AnsWer}$

Length = 5m

Breath = 1.3m

Area ( Outer ) = L × B

⠀⠀⠀⠀⠀⠀⠀⠀⠀= 5 × 1.3 = 6.5m²

⠀⠀⠀⠀⠀⠀⠀⠀⠀= 6.5 × 100 × 100

⠀⠀⠀⠀⠀⠀⠀⠀⠀= 65000 m.

⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of inner = L × B

⠀⠀⠀Length ( I ) = 5 - 50 = 4.50 × 100

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 450 cm.

⠀⠀⠀Breadth ( I ) = 1.3 - 50 = 80 × 100

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 80 cm.

⠀⠀⠀⠀⠀⠀⠀⠀⠀

A = L × B = 450 × 8

⠀⠀⠀⠀⠀⠀= 36000.

⠀⠀⠀⠀⠀⠀⠀⠀⠀

Area of Border = Outer area - Inner area

⠀⠀⠀⠀⠀⠀⠀⠀⠀ = 65000 - 36000

⠀⠀⠀⠀⠀⠀⠀⠀⠀= 29000 cm².

Total cost = Area × Cost per cm²

⠀⠀⠀⠀⠀⠀⠀$= 29000 \times \frac{1}{2}$

⠀⠀⠀⠀⠀⠀⠀= ₹2900 .