Question

find the largest numbers which when divides 98 120 153 leaves the same reminder​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Required largest number is 11.

Step-by-step explanation:

Given numbers are 98, 120, 153

As we have to find largest number which divides 98,120,135 leaving same remainder in each case.

Since the remainders are the same the difference of every pair of given numbers would be exactly divisible by

the required number

$120 - 98 = 22 \: \\ \: 153 - 120 = 33 \\ : 153 - 98 = 55$

∴ Required number = HCF of 22,33,55

Now,

$22 = 2 \times 11 \\ 33 = 3 \times 11 \\ 55 = 5 \times 11$

So,

$HCF = 11$

Required largest number is 11.