Question

A satellite close to the earth at a height of about 200km has a orbital speed of 8km/s. Taking the radius of the orbit as approximately equal to the earths radius of 6400km, calculate the time takes to make one orbit

Answer 1

Answer:

) we know, orbital speed at a height h, from the surface of the earth is given by,

Vo= √GM/r+h

a/c to question, the satellite orbits the earth at a height equal to the radius of earth.

so, h = R = 6400 km { from data }

now, orbital speed ,

= Vo = √GM/2r

√ 6.67×10-¹¹× 6×10²⁴/2×6.4×10^6

= 5.592 km/s

(ii) time period is given by,

here, h = R = 6400km

T = 2π(R + R)/5.592 × 10³

T = 2 × 3.14 × 2 × 6.4 × 10^6/5592

T = 14374.8 sec ≈ 4 hours