Question

A satellite is launched into a circular orbit of radius R around earth while a second satellite is launched into a orbit of radius 1.02R the percentage difference in the time period

Answer 1

Answer:

3%.

Explanation:

Here, we use Kepler's Third Law.

T² is proportional to R³.

Or T is proportional to R^(3/2).

Now using error analysis, we can say:

∆R% is (1.02-1) ×3/2 × 100

which is 3.

You can also do the whole calculation to come to the same result.