Question

a satellite is orbiting Earth at distance of 42000km in a circular orbit. It completes one revolution in 24 hours. calculate it's linear speed.​

Answer 1

The linear speed of the satellite is 10995.57 km/h.

Explanation:

It is given that,

Radius at which a satellite is orbiting Earth, r = 42000 km

Time taken to complete one revolution, t = 24 hours

We need to find the linear speed of satellite. It can be calculated by calculating total distance divided by total time taken. Total distance covered is equal to $2\pi r$. Speed is given by :

$v=\dfrac{2\pi r}{t}$

$v=\dfrac{2\pi\times 42000\ km}{24\ h}$

v = 10995.57 km/h

So, the linear speed of the satellite is 10995.57 km/h. Hence, this is the required solution.

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Answer 2

Answer:

Radius at which a satellite is orbiting Earth, r = 42000 km

Time taken to complete one revolution, t = 24 hours

We need to find the linear speed of satellite. It can be calculated by calculating total distance divided by total time taken. Total distance covered is equal to 2\pi r2πr . Speed is given by :

v=\dfrac{2\pi r}{t}v=

t

2πr

v=\dfrac{2\pi\times 42000\ km}{24\ h}v=

24 h

2π×42000 km

v = 10995.57 km/h