a satellite is orbiting just above the surface of a Planet of average density rho with the time period t then the universal constant of gravitation is given by
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Time period of satellite above the earth surface
T2=4π2R3GMT2=4π2R3GM
=3πG[M4/3πR3]=3πG[M4/3πR3]
=3π3ρ=3π3ρ
When ρρ=density of earth =Massofearthvolumeofearth=Massofearthvolumeofearth
=M43πR3=M43πR3
∴ρT2=3πG∴ρT2=3πG== constant
Hence a is the correct answer.
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T2=4π2R3GMT2=4π2R3GM
=3πG[M4/3πR3]=3πG[M4/3πR3]
=3π3ρ=3π3ρ
When ρρ=density of earth =Massofearthvolumeofearth=Massofearthvolumeofearth
=M43πR3=M43πR3
∴ρT2=3πG∴ρT2=3πG== constant
Hence a is the correct answer.
I hope it help you
mark me brainliest
follow me
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