A satellite is orbiting the earth at a height of 1000 km.find its orbital speed
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Sol. a) V = √GM/r + h = √gr^2/r + h
= √9.8 * (6400 * 10^3)^2/10^6 * (6.4 + 2) = 6.9 * 10^3 m/s = 6.9 km/s
b) K.E. = (1/2) mv^2
= (1/2) 1000 * (47.6 * 10^+6) = 2.38 * 10^10 J
c) P.E. = GMm/-(R + h)
= - 6.67 * 10^-11 * 6 * 10^24 * 10^3/(6400 + 2000) * 10^3 = - 40 * 10^-13/8400 = - 4.76 * 10^10 J
d) T = 2π(r + h)/V = 2 * 3.14 * 8400 * 10^3/6.9 * 10^3 = 76.6 * 10^2 sec = 2.1 hour
= √9.8 * (6400 * 10^3)^2/10^6 * (6.4 + 2) = 6.9 * 10^3 m/s = 6.9 km/s
b) K.E. = (1/2) mv^2
= (1/2) 1000 * (47.6 * 10^+6) = 2.38 * 10^10 J
c) P.E. = GMm/-(R + h)
= - 6.67 * 10^-11 * 6 * 10^24 * 10^3/(6400 + 2000) * 10^3 = - 40 * 10^-13/8400 = - 4.76 * 10^10 J
d) T = 2π(r + h)/V = 2 * 3.14 * 8400 * 10^3/6.9 * 10^3 = 76.6 * 10^2 sec = 2.1 hour
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