Question

A satellite is placed in circular orbit 3.2 x 10^6m above the earth. What is the orbital speed of the satellite? What is the period?

Answer 1

v=root of gR
root [9.8*3.2*10^6]
root [31.36*10^6]
=5.6*10^6
T=2pie root [R/g]
2 pie 571.43
=6.28s.