Physics, asked by Saba8827, 7 months ago

A satellite is revolving round the earth in an orbit of radius
r with time period T. If the satellite is revolving round the
earth in an orbit of radius r + ∆r (∆r << r) with time period T
+ ∆ T then,
(a)∆T/T = 3/2 ∆r/r
(b)∆T/T = 2/3 ∆r/r (c)∆T/T = ∆r/r
(d)∆T/T = -∆r/r

Answers

Answered by unnatigaur
0

Answer:

Answer:

3/2∆r/r

Explanation:

T^2proportional to R^3

∆T/T=∆R/R

2∆T/T=3∆R/R

∆T/T=3/2×∆R/R

hope it helps you..

Similar questions